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...Factor the expression: x^2-x-6. -6 can be considered as a product of 2 and -3 and gives us conclusion that -x can be written as a sum of -3x and 2x. So, our expression has this form now: x^2-3x+2x-3*2=x*(x-3)+2*(x-3)=(x+2)*(x-3). So, our quadratic equation looks like this: (x+2)*(x-3)=0. This will be equal to zero only if: x+2=0 or x-3=0.

...I believe that my abilities to successfully navigate both a BS and MS program at a highly competitive and highly ranked research university (UCSD) shows that I have mastered effective study skills. During my graduate program I taught as a TA for 10 quarters where I spent approximately 6-7 unsupe...

I took a course on Discrete Mathematics as part of my distributed minor when pursuing a Ph.D. in Computer Sciences. During my teaching career I've taught an equivalent course, Computational Mathematics, several times. I've also covered some of the topics of this subject within other courses, such as Network Flows, Calculus and Scientific Computing.

I have taken Calculus since my senior year of high school. I am currently enrolled in differential equations, and passed Calculus 1, 2, and 3 with grades of B or better. I also have taken 3 physics classes at the college sophomore level that are calculus based.

Extensive experience tutoring Algebra 1 topics. These included solving linear equations in two variables both **algebra**ically and graphically; solving quadratic equations by factorization and by utilizing the quadratic formula. Also taught foundational concepts in Algebra such as the number line, inequalities, roots, and functions.

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